SOLUTION: How do you solve:
Greg Brueck has a .78 chance of making par on each hole of golf that he plays. Today he plans to play just three holes. Find the probability that he makes par
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Question 371641: How do you solve:
Greg Brueck has a .78 chance of making par on each hole of golf that he plays. Today he plans to play just three holes. Find the probability that he makes par on at least one of the three holes.
Thank you!
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
x=.78, y=.22
(x+y)^3
y^3=.0106 probability of NOT paring any hole.
1-.0106=.9894 the probability that he makes par on at least one of the three holes.
.
Ed
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