SOLUTION: Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Which is the probability if the first marble is blue and the second marble is

Question 367178: Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Which is the probability if the first marble is blue and the second marble is white.
A) 3/7
B) 3/56
C) 2/7
D) 3/64
Found 2 solutions by edjones, stanbon:
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
There are 8 marbles.
1/8 * 3/7 = 3/56
.
Ed
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Which is the probability if the first marble is blue and the second marble is white.
P(blue) = 1/8
P(white|blue) = 3/7
P(1st blue and 2n white) = P(blue)*P(white|blue) = (1/8)(3/7) = 3/56
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Cheers,
Stan H.
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A) 3/7
B) 3/56
C) 2/7
D) 3/64

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