# SOLUTION: An urn contains 15 balls identical in every respect except color. There are 4 red balls, 8 green balls, and 3 blue balls. (a) You draw two balls from the urn but replace the fir

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: An urn contains 15 balls identical in every respect except color. There are 4 red balls, 8 green balls, and 3 blue balls. (a) You draw two balls from the urn but replace the fir      Log On

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 Algebra: Probability and statistics Solvers Lessons Answers archive Quiz In Depth

 Question 364123: An urn contains 15 balls identical in every respect except color. There are 4 red balls, 8 green balls, and 3 blue balls. (a) You draw two balls from the urn but replace the first ball before drawing the second. Find the probability that the first ball is red and the second is green. (b) Repeat part (a) but do not replace the first ball before drawing the second Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website!``` Hi, 15 balls f which 4 are red, 8 are green, and 3 are blue With replacement of the first ball P(first ball is red and the second is green) = 4/15 * 8/15 = 32/225= .142 without replacement (14 total balls in the urn on the second draw) P(first ball is red and the second is green) = 4/15 * 8/14 = 32/210 = .152 ```