SOLUTION: The diameter of apples in a certain orchard are normally distributed with a mean of 5.5 inches and a standard deviation of 0.65 inches. Show all work. What percentage of the app

Algebra ->  Probability-and-statistics -> SOLUTION: The diameter of apples in a certain orchard are normally distributed with a mean of 5.5 inches and a standard deviation of 0.65 inches. Show all work. What percentage of the app      Log On


   

Question 363489: The diameter of apples in a certain orchard are normally distributed with a mean of 5.5 inches and a standard deviation of 0.65 inches. Show all work.
What percentage of the apple in this orchard have diameters less than 5.8 inches?

What percentage of the apples in this orchard are larger than 6.3 inches?



I can work the first part but I don't undersand how to get the second part. Can anyone show me what to do?
z(5.8) = (5.8 -5.55)/0.65 = 0.385
P(x < 5.8) = P(z < 0.385) = ?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First, your z value is off (you used 5.55 instead of 5.5).
z%5B1%5D=%28x-mu%29%2Fsigma=%285.8-5.5%29%2F0.65=0.462
P%28z%5B1%5D%29=0.678
67.8%
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z%5B2%5D=%286.3-5.5%29%2F0.65=1.231
P%28z%5B2%5D%29=0.891
89.1% of apples have diameter less than or equal to 6.3.
100%-89.1%=10.9% have diameters greater than 6.3.
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