SOLUTION: I see where someone have asked the same question and it said that it had been answered but I could not find where it was answered. If it have been answered, can I be shown where; i

Question 362698: I see where someone have asked the same question and it said that it had been answered but I could not find where it was answered. If it have been answered, can I be shown where; if not can it be answered for me?
1.) Assume that the population of heights of male college students is approximately normally distributed with the mean of 69 inches and standard deviation of 3.75 inches. Show all work.
(A). Find the proportion of male college students whose height is greater than 70 inches.
(B). Find the proportion of male college students whose heights is no more than 70 inches.

(2). Find the normal approximation for the binomial probability that x = 6, where n = 15 and p = 6.

(3). A set of data is normally distributed with a mean of 200 and standard deviation of 50.
*what would be the standard score for a score of 167?
*what percentage of scores is between 200 and 167?
*what would be the percentile rank for a score of 167?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1.) Assume that the population of heights of male college students is approximately normally distributed with the mean of 69 inches and standard deviation of 3.75 inches. Show all work.
(A). Find the proportion of male college students whose height is greater than 70 inches.
---
z(70) = (70-69)/3.75 = 0.2667
P(x > 70) = P(z > 0.2667) = 0.3949

(B). Find the proportion of male college students whose heights is no more than 70 inches.
---
P(x<= 70) = 1-0.3949 = 0.6051
==============0.======================

(2). Find the normal approximation for the binomial probability that x = 6, where n = 15 and p = 6.
Find p(5.5 < x < 6.5) using mean = np=15*0.6 = 9
and std = sqrt(npq) = sqrt(9*0.4) = 1.8974
----
z(5.5) = (5.5-9)/1.8974 = -1.8447
z(6.5) = (6.5-9)/1.8974 = -1.3176
----
P(x=6) = P(-1.8447< z < -1.3176) = 0.0613
=================================================

(3). A set of data is normally distributed with a mean of 200 and standard deviation of 50.
*what would be the standard score for a score of 167?
z(167) = (167-200)/50 = -0.6600
===========
I'll leave the rest to you.
Cheers,
Stan H.
*what percentage of scores is between 200 and 167?
*what would be the percentile rank for a score of 167?
0 solutions

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