SOLUTION: find the n needed to obtain a p-hat between (p-0.01, p+0.01) with 95% probability
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Question 362466: find the n needed to obtain a p-hat between (p-0.01, p+0.01) with 95% probability
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the n needed to obtain a p-hat between
(p-0.01, p+0.01) with 95% probability.
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n = [z/E]^2*pq
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n = [1.96/0.01]^2*(1/2)(1/2)
----
n = 9604
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Cheers,
Stan H.
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