SOLUTION: Billy has 5 coins, 1 penny, 1 nickel, 1 dime, 1 quarter, and 1 half-dollar. How many different sums of money can Billy form by using 1, 2, or 3 of these coins?
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Question 361724: Billy has 5 coins, 1 penny, 1 nickel, 1 dime, 1 quarter, and 1 half-dollar. How many different sums of money can Billy form by using 1, 2, or 3 of these coins?
Found 2 solutions by solver91311, edjones:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You need:
)
which is the number of combinations of 
things taken 
at a time and is calculated by !})
Specifically: \ =\ \frac{5!}{3!(5\,-\,3)!})
. You get to do your own arithmetic.
John
My calculator said it, I believe it, that settles it
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
1) 5
.
2) 5C1*4C1=20
.
3) 5C1*4C2*3C1=60
.
Ed
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