# SOLUTION: You are dealt 2 cards from a shuffled deck of 52 cards, without replacement. There are four suits of 13 cards each in a deck of cards; two of them are black and two of them are red

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: You are dealt 2 cards from a shuffled deck of 52 cards, without replacement. There are four suits of 13 cards each in a deck of cards; two of them are black and two of them are red      Log On

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 Click here to see ALL problems on Probability-and-statistics Question 353235: You are dealt 2 cards from a shuffled deck of 52 cards, without replacement. There are four suits of 13 cards each in a deck of cards; two of them are black and two of them are red. What is the probability that both cards are black? Round your answer to 3 decimal places Found 2 solutions by sudhanshu_kmr, ewatrrr:Answer by sudhanshu_kmr(1152)   (Show Source): You can put this solution on YOUR website! No. of ways to select 2 cards from total 52 cards = 52C2 No. of ways to select 2 cards from 26 black cards = 26C2 required probability = 26C2 / 52C2 = 325 / 1326 = 0.245 Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website!Hi, . Note: There are 26 Black cards out of the 52 cards (there will be 25 out of 51 after the first black card has been dealt) . the probability that both cards dealt are black is: P(1st one being black)*P(2nd one being black) . (26/52)*(25/51) = .245