SOLUTION: You are dealt 2 cards from a shuffled deck of 52 cards, without replacement. There are four suits of 13 cards each in a deck of cards; two of them are black and two of them are red

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: You are dealt 2 cards from a shuffled deck of 52 cards, without replacement. There are four suits of 13 cards each in a deck of cards; two of them are black and two of them are red      Log On

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Question 353235: You are dealt 2 cards from a shuffled deck of 52 cards, without replacement. There are four suits of 13 cards each in a deck of cards; two of them are black and two of them are red. What is the probability that both cards are black? Round your answer to 3 decimal places
Found 2 solutions by sudhanshu_kmr, ewatrrr:
Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

No. of ways to select 2 cards from total 52 cards = 52C2

No. of ways to select 2 cards from 26 black cards = 26C2

required probability = 26C2 / 52C2

= 325 / 1326

= 0.245

Answer by ewatrrr(10682) About Me  (Show Source):
You can put this solution on YOUR website!
Hi,
.
Note: There are 26 Black cards out of the 52 cards (there will be 25 out of 51 after the first black card has been dealt)
.
the probability that both cards dealt are black is:
P(1st one being black)*P(2nd one being black)
.
(26/52)*(25/51) = .245