The probability that the first one you draw will be the only one you have drawn of that color, whatever it is, is 1 because that is certain, since you will have only drawn one. The probability that the second one you draw will be the only one you have drawn of that color, whatever it is, isbecause it can be any of the three colors that you didn't draw the first time. The probability that the third one you draw will be the only one you have drawn of that color, whatever it is, is because it can be either of the two colors that you didn't draw the first or second times. The probability that the third one you draw will be the only one you have drawn of that color, whatever it is, is because it must be the only color you haven't drawn. So the desired probability is Edwin