SOLUTION: There is a committee of 4 people. There are 5 teachers and 20 parents to choose for this committee. What is the probability that:
A: All are teachers?
B: Two are teachers and two
Algebra.Com
Question 352126: There is a committee of 4 people. There are 5 teachers and 20 parents to choose for this committee. What is the probability that:
A: All are teachers?
B: Two are teachers and two are parents?
Found 2 solutions by ewatrrr, sudhanshu_kmr:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
*Note: The probability of x successes in n trials is:
.
P = nCx* * where p and q are the probabilities of success and failure respectively.
.
nCx =
.
Question states p(teacher drawn) = 5/25 0r .2 and q = .8
.
A.
4C4 =
.
P(4 teachers are selected) = = .0016
.
B.
4C2 =
.
P(2 teachers and 2 parents) =
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!
No. of ways to choose 4 people from total 25 people = 25C4
(i.e no. of sample space)
A:
No. of ways to choose 4 people from 5 teachers = 5C4
probability of all 4 are teachers = no. of favourable event/ no. of sample space
= 5C4 / 25C4
= 5 / 12650
= 1 / 2530
..............................................................................
B.
No. of ways to choose 2 teachers and 2 parents = 5C2 * 20C2
= 10 * 190 = 1900
probability of 2 teachers and 2 parents = 1900 / 25C4
= 38 / 253
Sometimes there may be typing mistake in solution of a problem, so please ignore it. Understand the concept and try the problem yourself.
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