SOLUTION: 1300 x (1+.0925) to the 35th power
Algebra.Com
Question 349662: 1300 x (1+.0925) to the 35th power
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
You can do this with logs:
Take the log. Note that the log of a product
is the sum of the logs of the factors
This is the log of the answer.
Now you have to find
which is the antilog
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