SOLUTION: In a bag of candies there are 13 red candies, 13 green candies, 13 yellow candies, and 13 blue candies. If you choose 1 candy from the bag, what is the probability the candy will n
Algebra.Com
Question 349004: In a bag of candies there are 13 red candies, 13 green candies, 13 yellow candies, and 13 blue candies. If you choose 1 candy from the bag, what is the probability the candy will not be blue?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(13*3)/(13*4)=.75 probability the candy will not be blue.
RELATED QUESTIONS
If I have a bag that has 13 red candies, 13 yellow candies, 13 green candies and 13 blue... (answered by ewatrrr)
A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7... (answered by ikleyn)
A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7... (answered by Boreal)
I Got 2 Questions.
1.In a gym class, there are 12 boys and 18 girls. If the teacher... (answered by solver91311)
1. There are 4 contestants in a bicycle race. In how many different orders can they cross (answered by stanbon)
In a bag of candy, there are five red candies for every two green candies. If there are... (answered by stanbon)
In a bag of M&M's the ratio of red candies to green candies is 5:4.
If there are 378 red (answered by rfer)
A bag of M&M's contained 13 red, 15 yellow, 44 brown, 12 orange, and 9 green candies.... (answered by josgarithmetic)
A bag of M&M's contained 13 red, 15 yellow, 44 brown, 12 orange, and 9 green candies.... (answered by josgarithmetic)