SOLUTION: Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. What is the probability that both marbles are white? Please answer in fraction

Question 34742: Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. What is the probability that both marbles are white? Please answer in fraction form.
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
N(S) is the number of possible ways from the entire sample space.
Two marbles drawn from a total of 8 marbles
=> N(S) = C(8,2) = 8*7/2 = 28
There are 28 all possible ways in which any two marbles can be drawn from the pool.
N(E) = Number of ways so that both marbles are white.
There are 3 white balls.
N(E) = C(3,2) = 3*2/2 = 3
There are 3 possible ways in which any two white marbles can be drawn from 3 white marbles.
Probability of drawing two white marbles = N(E)/N(S) = 3/28;
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