SOLUTION: Component 1 has an exponential failure rate of 2X10exp-2 failures per hour. component 2 is normally distributed with a mean of 200 hours and standard deviation of 50 hurs. Assuming
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Question 345425: Component 1 has an exponential failure rate of 2X10exp-2 failures per hour. component 2 is normally distributed with a mean of 200 hours and standard deviation of 50 hurs. Assuming independence, calculate the reliability of the system after 50 hours.
------Component 1----------component 2---------------
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Component 1 has an exponential failure rate of 2X10exp-2 failures per hour. component 2 is normally distributed with a mean of 200 hours and standard deviation of 50 hrs. Assuming independence, calculate the reliability of the system after 50 hours.
------
Component 1----------
reliability rate = (1-(2x10^-2))^50 = 0.3642
---------------------
component 2----------
z(50) = (50-200)/50 = -3
reliability = 1 - P(z< -3) = 1-0.0013 = 0.9987
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Cheers,
Stan H.
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