SOLUTION: While I can get the answer in a long handed table I am sure that a formula exists for this: From a group of six people, two individuals are to be selected at random. How many pos

Question 342300: While I can get the answer in a long handed table I am sure that a formula exists for this: From a group of six people, two individuals are to be selected at random. How many possible selections are there?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
This would be the combination formula of n! / (x! * (n-x)!) where:

n = total number of people (6 in your case).

x = number of people to be selected at one time (2 in your case).

The formula for you becomes 6! / (2! * 4!) which becomes 6*5/2 which becomes 15.

If we assume the people are abcdef, then the possible ocmbinations are:

ab
ac
ad
ae
af
bc
bd
be
bf
cd
ce
cf
de
df
ef

This assumes the order in which they are selected is not important.

None of the sets has the same 2 people in them, regardless of order.

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