SOLUTION: A doll toy chest contains 6 yellow dolls and five orange dolls. What is the probability of getting at random and without replacement, 2 yellow dolls?

Question 334468: A doll toy chest contains 6 yellow dolls and five orange dolls. What is the probability of getting at random and without replacement, 2 yellow dolls?
Found 2 solutions by Fombitz, jrfrunner:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Y-yellow
O-orange
total,
.
.
.
P(1 Y)=
P(2 Y)=
P(both Y)=
Answer by jrfrunner(365) (Show Source): You can put this solution on YOUR website!
A doll toy chest contains 6 yellow dolls and five orange dolls. What is the probability of getting at random and without replacement, 2 yellow dolls?
--
Total dolls = 11
let Y= yellow dolls
let O=orange dolls
--
probability of getting at random and without replacement, 2 yellow dolls
P(YY)=P(Y on first choosing)*P(Y on second choosing / First choosing is Y)
P(YY)= (6/11)*(5/10)=(6/11)*(1/2)=3/11
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you first have 6 yellow dolls to choose from 11 dolls, after you make that selection, your total is reduced by 1 to 10 and if that was yellow, the yellows are reduced by 1 to 5 (since its without replacement)
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