SOLUTION: a jury is made up of 2 males and 8 females. Two jurors are selected at random for a follow up interview. Find the probability that both are males
Algebra.Com
Question 330678: a jury is made up of 2 males and 8 females. Two jurors are selected at random for a follow up interview. Find the probability that both are males
Found 2 solutions by solver91311, jrfrunner:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The probability of 
successes in 
trials where 
is the probability of success on any given trial is given by:
\ =\ \left(n\cr k\right\)p^k\left(1\,-\,p\right)^{n\,-\,k})
Where )
is the number of combinations of things taken at a time and is calculated by !})
You need 2 successes in 2 trials where the probability of success on one trial is 
.
\ =\ \left(2\cr 2\right\)(0.2)^2\left(0.8\right)^0)
Which looks like a bunch of nasty arithmetic until you consider that:
\ =\ 1)
and
So:
\ =\ (0.2)^2)
John
My calculator said it, I believe it, that settles it
Answer by jrfrunner(365) (Show Source): You can put this solution on YOUR website!
choosing a male first and then choosing a second male are not independent events so......
probability that both are males =P(MM) =P(M first)*P(M second/M first)=2/10*1/9 = 2/90=0.022
first there are 2/10 chance of choosing a male, but once this male is selected the pool is reduced to 1 male in 9 jurors
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