SOLUTION: The Human Resources Director for a large company is studying absenteeism among hourly workers. A sample of 120 day shift employees showed 15 were absent more than five days last ye

Question 327054: The Human Resources Director for a large company is studying absenteeism among hourly workers. A sample of 120 day shift employees showed 15 were absent more than five days last year. A sample of 80 afternoon employees showed 18 to be absent five or more times. At the 0.01 significance level can we conclude that there is a higher proportion of absenteeism among afternoon employees?
a. State the null and alternate hypotheses.
b. State the decision rule.
c. Compute the value of the test statistic.
d. Compute the p-value.
e. What is your decision regarding the null hypothesis?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The Human Resources Director for a large company is studying absenteeism among hourly workers.
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A sample of 120 day shift employees showed 15 were absent more than five days last year.
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A sample of 80 afternoon employees showed 18 to be absent five or more times.
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At the 0.01 significance level can we conclude that there is a higher proportion of absenteeism among afternoon employees?
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a. State the null and alternate hypotheses.
Ho: p(aft)-p(day) = 0
Ha: P(aft)-p(day) > 0
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b. State the decision rule.
reject Ho if ts > 2.3263
==============================
c. Compute the value of the test statistic.
I ran a 2-PropZtest and got:
z = 1.8665
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d. Compute the p-value.
P(z > 1.8665) = 0.0310
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e. What is your decision regarding the null hypothesis?
Since the p-value is greater than 1%, fail to reject Ho.
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Cheers,
Stan H.
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