SOLUTION: event A occurs with probabity 0.1. Event B occurs with probability 0.6. if A and B are independant, then :
a- p(a and b)= 0.70
b- p(a or b)= 0.64
c- p(a and b)= 0.64
d- p(a o
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Question 326907: event A occurs with probabity 0.1. Event B occurs with probability 0.6. if A and B are independant, then :
a- p(a and b)= 0.70
b- p(a or b)= 0.64
c- p(a and b)= 0.64
d- p(a or b)= 0.70
thanks
Found 2 solutions by stanbon, jrfrunner:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
event A occurs with probabity 0.1. Event B occurs with probability 0.6. if A and B are independant, then P(a and b) = (0.1*0.6) = 0.06
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Cheers,
Stan H.
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a- p(a and b)= 0.70
b- p(a or b)= 0.64
c- p(a and b)= 0.64
d- p(a or b)= 0.70
Answer by jrfrunner(365) (Show Source): You can put this solution on YOUR website!
if A and B are independent then P(A and B) = P(A)*P(B) = 0.1*0.6=0.06
also P(A or B) = P(A)+P(B)-P(A and B)= P(A)+P(B)-P(A)*P(B)
= 0.1 +0.6-0.1*0.6=0.7-0.06=0.64
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