Question 325728: A pair of fair dice is rolled. Find the probability that the sum of the two numbers facing up is less than 10. Found 2 solutions by stanbon, solver91311:Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! A pair of fair dice is rolled. Find the probability that the sum of the two numbers facing up is less than 10.
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Total number of sums: 36
# of 12's: 1
# of 11's: 2
# of 10's; 3
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# less than 10: 30
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P(sum < 10) = 30/36
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Cheers,
Stan H. Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Sum
Ways
# of Ways
2
1,1
1
3
1,2; 2,1
2
4
1,3; 2,2; 3,1
3
5
1,4; 2,3; 3,2; 4,1
4
6
1,5; 2,4; 3,3; 4,2; 5,1
5
7
1,6; 2,5; 3,4; 4,3; 5,2; 6,1
6
8
2,6; 3,5; 4,4; 5,3; 6,2
5
9
3,6; 4,5; 5,4; 6,3
4
10
4,6; 5,5; 6,4
3
11
5,6; 6,5
2
12
6,6
1
The probability of anything is the number of ways that it can happen that you would consider a success divided by the number of ways it can happen total -- successes and failures.
If you add up the number of total ways that you can roll a pair of dice you get 36. There are 3 ways to get a ten, 2 ways to get an 11 and 1 way to get a 12, so there must be 36 minus 6 (3 plus 2 plus 1) ways to get less than 10.