SOLUTION: The mean price of computers at an electronics store is $850, with a standard deviation of $90. A random sample of 21 televisions is drawn from this population. What is the probabil
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Question 321276: The mean price of computers at an electronics store is $850, with a standard deviation of $90. A random sample of 21 televisions is drawn from this population. What is the probability that the mean price of the sample is less than $830? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The mean price of computers at an electronics store is $850, with a standard deviation of $90.
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A random sample of 21 televisions is drawn from this population. What is the probability that the mean price of the sample is less than $830?
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mean of the distribution of sample means = 850
std of the distribution of sample means = 90/sqrt(21)
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t(830) = (830-850)/[0.90/sqrt(21)] = -1.0184
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P(x< 830) = P(t< -1.0184 when df=20) = 0.1603
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Cheers,
Stan H.
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