SOLUTION: The mean is u=60 and its stardard devation is q=4.0
Find the probability that X is less that 53
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Question 319482: The mean is u=60 and its stardard devation is q=4.0
Find the probability that X is less that 53
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The mean is u=60 and its standard deviation is q=4.0
Find the probability that X is less that 53
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z(53) = (53-60)/4 = -7/4
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P(x < 53) = P(z < -7/4) = normalcdf(-1000,-7/4) = 0.0401
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Cheers,
Stan H.
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