SOLUTION: Can anyone help me with this probability question? A box has the following six letters: R A N D O M . What is the probability of the outcome D A N in that order if three letters

Question 318955: Can anyone help me with this probability question? A box has the following six letters: R A N D O M . What is the probability of the outcome D A N in that order if three letters are drawn one by one 1)with replacement 2) without replacement? I could make a chart or tree if there were only two letters but I'm not sure how to solve with three. I know I've got one in six chances to pull individual letters, but I'm not sure how to work the other factors in. Any help would be appreciated!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A box has the following six letters: R A N D O M .
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What is the probability of the outcome D A N in that order if three letters are drawn one by one
1)with replacement
1st letter "D": 1/6
2nd letter "A"; 1/6
3rd letter "N": 1/6
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Probability of outcome DAN with replacement = (1/6)^3 = 1/216
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2) without replacement?
1st letter "D": 1/6
2nd letter "A": 1/5
3rd letter "N": 1/4
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Probability of outcome DAN without replacement = 1/(6*5*4) = 1/120
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Cheers,
Stan H.
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