SOLUTION: The time to wait for a particular rural bus is distributed unifromly from 0 to 75 minutes. 100 riders are randomly sampled to learn how long they waited. What is the 90th perce

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 Question 315070: The time to wait for a particular rural bus is distributed unifromly from 0 to 75 minutes. 100 riders are randomly sampled to learn how long they waited. What is the 90th percentile sample average wait time (in minutes) for a sample of 100 riders? mean = 0+75/2 = 37.5 I think I enter the numbers into my scientific calculator under distribution and inverse normal ( percentile, mean, stand dev. / square root of 100) or (.90, 37.5, ?)?? I can't figure out how to get the standard deviation....thank you thank you thank youAnswer by stanbon(57224)   (Show Source): You can put this solution on YOUR website! The time to wait for a particular rural bus is distributed unifromly from 0 to 75 minutes. 100 riders are randomly sampled to learn how long they waited. What is the 90th percentile sample average wait time (in minutes) for a sample of 100 riders? mean = 0+75/2 = 37.5 I think I enter the numbers into my scientific calculator under distribution and inverse normal ( percentile, mean, stand dev. / square root of 100) or (.90, 37.5, ?)?? ------------------------- I can't figure out how to get the standard deviation.... Comment: Please consider this. The range of the data is generally considered to 6sigma. Your data range is 0 to 75. If 6sigma = 75, sigma = 12.5 ================================ Cheers, Stan H.