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put this solution on YOUR website!A statistician is considering using a 99% confidence interval for a study instead of a 95% confidence interval. What happens to the required sample size if the confidence level is increased from 95% to 99% and the same error is required in each case?
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Since n = [zs/E}^2, n is directly proportion to z^2.
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So, if confidence goes up, that forces z to go up, so n must go up.
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Cheers,
Stan H.