# SOLUTION: 5. A mutual fund manager is reviewing her account status and finds that the account population is normally distributed with a mean of \$60,000 and a standard deviation of \$6,000.

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: 5. A mutual fund manager is reviewing her account status and finds that the account population is normally distributed with a mean of \$60,000 and a standard deviation of \$6,000.       Log On

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 Click here to see ALL problems on Probability-and-statistics Question 312128: 5. A mutual fund manager is reviewing her account status and finds that the account population is normally distributed with a mean of \$60,000 and a standard deviation of \$6,000. a. If she selects an account at random, what is the probability the account will have a value between \$60,000 and \$69,000? _______ b. If she selects an account at random, what is the probability the account will have a value between \$51,000 and \$66,000? ________ c. If she selects an account at random, what is the probability the account will have a value less than \$55,000? ________ d. If she selects an account at random, what is the probability the account will have a value greater than \$72,000? ________ Answer by Fombitz(13828)   (Show Source): You can put this solution on YOUR website!a) Find the z score for 60000 and 69000 P(60K< x <69K)=P(1.5)-P(0)=0.93319-0.5= . . . b) Find the z score for 55000 P(51K< x < 66K)=0.841345-0.066807= . . . c) Find the z score for 55000 P(x <55K)= . . . d) Find the z score for 72000 P(x <72K)= P(x >72K)=1-P(x <72K)=1-0.97725= . . .