_
x = 61.7,  = 14

: 
: 




No, we cannot reject the claim at  because z 
is neither less than -1.96 nor greater than 1.96.

We could also do it by computing the p-score, the probability
that xBAR would be at least as far off from 65 as 61.7 if the mean 
were actually 65.     

To find that p-score we find the area to the left of the z-score -1.29
as .5-.4015=.0985 and double it since this is a two-tail test.  That
gives the p-score of .197.

So we would only reject the null hypothesis if it were that .
But  is lower that that, only .05.

Edwin