SOLUTION: P(6 < x-bar < 8) = P(-0.3514 < z < +0.3514) = 0.2747 How did you get the 0.2747

Algebra.Com
Question 310258: P(6 < x-bar < 8) = P(-0.3514 < z < +0.3514) = 0.2747
How did you get the 0.2747

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
P(6 < x-bar < 8) = P(-0.3514 < z < +0.3514) = 0.2747
How did you get the 0.2747
--------------
z = 0.3514 has a left tail of 0.6374
---
z = -0.3514 has a left tail of 0.3626
----------------------------
Therefore the area between z = -0.3514 and +0.3514 is
0.6374-0.3626 = 0.2748 or 2748, depending on how/if
you round off the numbers.
===============================
Cheers,
Stan H.
=================

RELATED QUESTIONS

For a standard normal random variable Z, find the value of z0 such that (a) P(Z > z0) =... (answered by ewatrrr)
4. Compute the probability. a. If P(A) = 0.2 , P(B)= 0.4, and P(A and B) = 0.1, find... (answered by ikleyn)
Find the probabilities for each of the following. 1. P(0 < z < 2.0) 2. P(0 < z < 1.3)... (answered by ikleyn)
Triangle XYZ has vertices x(0, 0), y(10, 0), and z(0, 6). Triangle MYP has vertices M(5, (answered by KMST)
Determine whether the following equations have a solution or not and justify your answer. (answered by checkley71)
Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ (answered by Fombitz)
v*p=v but v doesn't =0 8*z=p v+5=t t+p=p what is the numerical value of p,t,v, and... (answered by Alan3354)
8) Find each of the following probabilities for a normal distribution. a) p(z > -1.00) (answered by stanbon)
Find the missing probability. P(A) = 0.5 P(B) = 0.6 P(A and B) = ? P(A) = 0.31... (answered by ikleyn)