SOLUTION: When it is not raining, the probability of the Buchanan Bears winning a football game is 2/3. When it is raining the probability of the Bears winning is 3/15. The probability of
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Question 310228: When it is not raining, the probability of the Buchanan Bears winning a football game is 2/3. When it is raining the probability of the Bears winning is 3/15. The probability of rain on any day in December is 3/4.
What is the probability of the Bears winning on December 5?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
When it is not raining, the probability of the Buchanan Bears winning a football game is 2/3. When it is raining the probability of the Bears winning is 3/15. The probability of rain on any day in December is 3/4.
What is the probability of the Bears winning on December 5?
-----------------------------------
P(win | not raining) = 2/3
------------------------------
P(win | raining) = 3/15
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P(rain) = 3/4
=================================
Question:
P(win) = P(win | rain) + P(win | not raining) = 3/15 + 10/15 = 13/15
==================================
Cheers,
Stan H.
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