SOLUTION: Students received an A in math class. 2 used in person tutors. 4 used on line tutors. 5 used no tutors. Students did not receive A in the math class. 34 used in person tutors, 5

Question 307051: Students received an A in math class. 2 used in person tutors. 4 used on line tutors. 5 used no tutors.
Students did not receive A in the math class. 34 used in person tutors, 53 used on line students. 20 used no students.
If the student from the whole group were randomly chose, what is the probability that the student use in person or on line tutors?
I think this is an addition rule.
P (A or B)= P(A) + P (B)-P (A-B)
36/118+ 57/118 - (93/118) = 0.000455
Thank you
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You are on the right track, but the third fraction is not . First off, notice how , so this would mean that the three fractions would combine to 0, which is not what we're looking for.

Instead, the third fraction is the product of the two first fraction.
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