SOLUTION: I see that the Alpha is different and is at a = 0.05,How do I do this one The players on last year�s football team at State College were able to bench press a mean of 312 lb. Co

Question 303116: I see that the Alpha is different and is at a = 0.05,How do I do this one
The players on last year�s football team at State College were able to bench press a mean of 312 lb. Coach Juarez made it clear to the players during spring training that the team�s average best lift had to improve. A special weight-training program was launched, and all the players participated. In an effort to measure the team�s progress, the coach recorded the heaviest lifts of the starting offensive and defensive lineups at the start of this season. Results are as follows:
346 412 332 285 396 461 321 275
246 315 298 347 430 419 406 311

a. State the appropriate null and alternative hypotheses.

b. Calculate the test statistic.

c. At a = 0.05, should Coach Juarez reject the null hypothesis?

d. Assuming the starting lineup is a representative sample, what conclusion can the coach draw

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I see that the Alpha is different and is at a = 0.05,How do I do this one
The players on last year�s football team at State College were able to bench press a mean of 312 lb. Coach Juarez made it clear to the players during spring training that the team�s average best lift had to improve. A special weight-training program was launched, and all the players participated. In an effort to measure the team�s progress, the coach recorded the heaviest lifts of the starting offensive and defensive lineups at the start of this season. Results are as follows:
346 412 332 285 396 461 321 275
246 315 298 347 430 419 406 311
--------------------------------------
The mean of the sample is 350
The std of the sample is 63.18
n = 16 ; df = 15
----------------------------------
a. State the appropriate null and alternative hypotheses.
Ho: u = 312
Ha: u > 312
--------------------
b. Calculate the test statistic.
t(350) = (350-312)/[63.18/sqrt(16)] = 2.4058
--------------------
c. At a = 0.05, should Coach Juarez reject the null hypothesis?
p-value = P(t > 2.4058 when df = 15) = 0.0147
---
Since the p-value is less than 5%, reject Ho.
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d. Assuming the starting lineup is a representative sample, what conclusion can the coach draw.
The training program was beneficial.
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Cheers,
Stan H.

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