SOLUTION: 1. The following data show samples of three chain stores in three different locations in one town and the amount of dollars spent per customer per visit. Management wishes to test

Question 302208: 1. The following data show samples of three chain stores in three different locations in one town and the amount of dollars spent per customer per visit. Management wishes to test whether each shopper is spending an equal amount of money at each store.
Store A Store B Store C
14 26 9
48 32 13
36 34 8
31 8 22
42 37 14
43 16

Perform a one-way analysis of variance on these data, assuming = 0.05:
� State the null and alternate hypotheses
� Calculate the sums of squares SS(total), SS(factor), and SS(error)
� Calculate the degrees of freedom df(total), df(factor), and df(error)
� Calculate the mean square for factor, and the mean square for error
� Calculate the F-statistic
� Determine the critical value(s)
� State your decision: Should the null hypothesis be rejected?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The following data show samples of three chain stores in three different locations in one town and the amount of dollars spent per customer per visit. Management wishes to test whether each shopper is spending an equal amount of money at each store.
Store A Store B Store C
14 26 9
48 32 13
36 34 8
31 8 22
42 37 14
43 16

Perform a one-way analysis of variance on these data, assuming = 0.05:
� State the null and alternate hypotheses
Ho: the means are equal
Ha: the means are not all equal
---
� Calculate
the sums of squares SS(total) = 341.33
SS(factor) =
SS(error)= 1453.33
-------------------------------------------
� Calculate the degrees of freedom
df(total)
df(factor) = 2
df(error) = 9
-------------------------------------------
� Calculate the mean square for factor, and the mean square for error
� Calculate the F-statistic = 1.0569
� Determine the critical value(s)
� State your decision: Should the null hypothesis be rejected?
The p-value is 0.3870
Since the p-value is greater than 5%, fail to reject Ho.
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Cheers,
Stan H.
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