SOLUTION: at a local clinic there are 8 men, 5 women,and 3 children in the waiting room.If three patients are randomly selected, find the probability that there is at least 1 child among the

Question 297183: at a local clinic there are 8 men, 5 women,and 3 children in the waiting room.If three patients are randomly selected, find the probability that there is at least 1 child among them.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
at a local clinic there are 8 men, 5 women,and 3 children in the waiting room.If three patients are randomly selected, find the probability that there is at least 1 child among them.
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P(at least one child) = 1 - P(no child)
P(x>=1) = 1 - 3C0(3/16)^0*(13/16)^3 = 1-(13/16)^3 = 0.4636
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cheers,
Stan H.
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