SOLUTION: The National Safety Council reported that 52% of American turnpike drivers are men. A sample of 300 cars traveling southbound on the New Jersey Turnpike yesterday revealed that 170

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 Question 295962: The National Safety Council reported that 52% of American turnpike drivers are men. A sample of 300 cars traveling southbound on the New Jersey Turnpike yesterday revealed that 170 were driven by men. At the .01 significance level, can we conclude that a larger proportion of men were driving on the New Jersey Turnpike than the national statistics indicate? First state H0 & Ha a) Is this a Z or t test b) Test statistic =? c) Critical value =? d) P-value =? e) Reject Ho: (yes or no) Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website! The National Safety Council reported that 52% of American turnpike drivers are men. A sample of 300 cars traveling southbound on the New Jersey Turnpike yesterday revealed that 170 were driven by men. At the .01 significance level, can we conclude that a larger proportion of men were driving on the New Jersey Turnpike than the national statistics indicate? First state H0 & Ha a) Is this a Z or t test Ans: Proportion tests are z tests --------------------------------------- b) Test statistic = t(170/300) = (0.57-0.52)/sqrt[0.52*0.48/300] = 1.733 --------------------------------- c) Critical value for right tail test with alpha=1% = 2.339 ------------------------------ d) P-value = P(t > 1.733) = tcdf(1.733,100,299) = 0.0421 -------------------------- e) Reject Ho: (yes or no) Since the p-value is greater less than 1%, fail to reject Ho. =================================== Cheers, Stan H. ===================================