SOLUTION: The National Safety Council reported that 52% of American turnpike drivers are men. A sample of 300 cars traveling southbound on the New Jersey Turnpike yesterday revealed that 170
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Question 295962: The National Safety Council reported that 52% of American turnpike drivers are men. A sample of 300 cars traveling southbound on the New Jersey Turnpike yesterday revealed that 170 were driven by men. At the .01 significance level, can we conclude that a larger proportion of men were driving on the New Jersey Turnpike than the national statistics indicate? First state H0 & Ha
a) Is this a Z or t test
b) Test statistic =?
c) Critical value =?
d) P-value =?
e) Reject Ho: (yes or no)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The National Safety Council reported that 52% of American turnpike drivers are men. A sample of 300 cars traveling southbound on the New Jersey Turnpike yesterday revealed that 170 were driven by men. At the .01 significance level, can we conclude that a larger proportion of men were driving on the New Jersey Turnpike than the national statistics indicate? First state H0 & Ha
a) Is this a Z or t test
Ans: Proportion tests are z tests
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b) Test statistic = t(170/300) = (0.57-0.52)/sqrt[0.52*0.48/300] = 1.733
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c) Critical value for right tail test with alpha=1% = 2.339
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d) P-value = P(t > 1.733) = tcdf(1.733,100,299) = 0.0421
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e) Reject Ho: (yes or no)
Since the p-value is greater less than 1%, fail to reject Ho.
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Cheers,
Stan H.
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