SOLUTION: A box contains exactly 5 red, 4 blue, and 3 green balls. If two balls are selected at random one after the other without replacing the first, what is the probability that the first

Question 292102: A box contains exactly 5 red, 4 blue, and 3 green balls. If two balls are selected at random one after the other without replacing the first, what is the probability that the first one is red and the second one is green?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A box contains exactly 5 red, 4 blue, and 3 green balls. If two balls are selected at random one after the other without replacing the first, what is the probability that the first one is red and the second one is green?
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A total of 12 balls.
5 of 12 chances for the 1st ball being red.
11 balls are left.
3 of 11 chances for the 2nd ball being green.
(5/12)*(3/11) = 5/44

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