SOLUTION: suppose you are playing a game in which 2 fair die are rolled. you need a 9 to land on finish by an exact count or a 3 to land on "roll again" space. what is the probability of la

Question 291606: suppose you are playing a game in which 2 fair die are rolled. you need a 9 to land on finish by an exact count or a 3 to land on "roll again" space. what is the probability of landing on the finish or rolling again. explain in detail.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
suppose you are playing a game in which 2 fair die are rolled.
you need a 9 to land on finish by an exact count or a 3 to land on "roll again" space. what is the probability of landing on the finish or rolling again. explain in detail.
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Rule: P(A or B) = P(A) + P(B) - P(A and B)
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Your Problem: The two events are mutually exclusive
so P(A and B) is zero.
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Ways to get a 9: 6/3;5/4;4/5;3/6
P(get a 9) = 4/36
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Ways to get a 3: 2/1;1/2
P(get a 3) = P(2/36)
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Ans: P(9 or 3) = 4/36 + 2/36 = 6/36 = 1/6
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Cheers,
Stan H.
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