SOLUTION: 2. A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Te

Question 286710: 2. A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager�s claim at the 3% significance level.
a. State the null and alternate hypothesis.
b. Determine the rejection region for the decision rule.
c. Which equation listed below would you use?
d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis. Provide a one sentence answer.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager�s claim at the 3% significance level.
a. State the null and alternate hypothesis.
Ho: p >= 0.45
Ha: p < 0.45
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b. Determine the rejection region for the decision rule.
invNorm(0.97) = -1.8808
Reject region is all z < -1.8808
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c. Which equation listed below would you use?
Equations were not listed.
-------------------------------
d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis.
---
stat test: z(150/400) = (0.375-0.45)/sqrt[0.45*0.55/400] = -3.0151
Provide a one sentence answer.
Since the test stat is in the rejection region, reject Ho.
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Cheers,
Stan H.

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