SOLUTION: It has been determined that the wait-time for a particular doctor is normally distributed with a mean of 28 minutes and a standard deviation of 2 minutes. What is the probability t
Algebra.Com
Question 285612: It has been determined that the wait-time for a particular doctor is normally distributed with a mean of 28 minutes and a standard deviation of 2 minutes. What is the probability that you will wait between 26 and 32 minutes? Please round the answer to four decimal places.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
It has been determined that the wait-time for a particular doctor is normally distributed with a mean of 28 minutes and a standard deviation of 2 minutes. What is the probability that you will wait between 26 and 32 minutes? Please round the answer to four decimal places.
-----------------------
Find the z-score of 26 and of 32 minutes:
---
z(26) = (26-28)/2 = -1
z(32) = (32-28)/ = 2
-------------------------
P(26< x < 32) = P(-1 < z < 2) = 0.8186
=========================================
Cheers,
Stan H.
RELATED QUESTIONS
Hi! Please help with the following question. Thanks!
In a certain doctors’ office... (answered by Theo)
Hi! Please help me out with this question!
In a certain doctors' office the waiting... (answered by ewatrrr)
The U.S. national average door-to-doctor wait time for patients to see a doctor is now... (answered by stanbon)
the time spent waiting in the line is approximately normally distributed. the mean... (answered by lynnlo)
the waiting time x at a certain bank is approximately normally distributed with a mean of (answered by ewatrrr)
pizza king has found that the time it takes to deliver a pizza is normally distributed... (answered by wilft1)
The time required to verify and fill a common prescription at a neighborhood pharmacy is... (answered by stanbon)
The IRS computes the time it takes filers to complete its forms. For a particular form,... (answered by Boreal)
1. A supermarket manager has determined that the amount of time customers spend in the... (answered by tommyt3rd)