SOLUTION: Five numbers are to be picked, without repitition, from 44 numbers to determine the winner of the Firtune Five game in the state lottery. If the order of the numbers is insignifica

Question 280208: Five numbers are to be picked, without repitition, from 44 numbers to determine the winner of the Firtune Five game in the state lottery. If the order of the numbers is insignificant, how many different ways can a winning quintuple be selected? What is the probability of winning?
Am I on the right track:
44*43*42*41*40=40,320,960 possible combinations
How do I find the probability?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Five numbers are to be picked, without repitition, from 44 numbers to determine the winner of the Firtune Five game in the state lottery. If the order of the numbers is insignificant, how many different ways can a winning quintuple be selected? What is the probability of winning?
---------------------
Am I on the right track:
44*43*42*41*40=40,320,960 possible combinations
That's 130320960
How do I find the probability?
--------------------
That's the start, but because the order doesn't matter, there are 5 chances for the 1st number to be selected, 4 chances for the 2nd, etc, so you divide by
5*4*3*2*1, or 5!
= 44*43*42*41*41/120 = 130320960/120 = 1 chance out of 1086008
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