SOLUTION: An ad clims " 1 in 7 will be hospitalzed this year." Suppose in a sample of 180 people and assuming the claim of ad correct what is the probability that fewer than 10% of people in

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 Click here to see ALL problems on Probability-and-statistics Question 277940: An ad clims " 1 in 7 will be hospitalzed this year." Suppose in a sample of 180 people and assuming the claim of ad correct what is the probability that fewer than 10% of people in the sample will be found to have been hospitalized (at least once) in the year?Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!An ad claims " 1 in 7 will be hospitalzed this year." Suppose in a sample of 180 people and assuming the claim of ad correct what is the probability that fewer than 10% of people in the sample will be found to have been hospitalized (at least once) in the year? ---------------------- Binomial Problem: n = 180 10% of 180 is 18 people p = 1/7 P(0<= x <=17) = ? Using a TI calculator to find that probability I get: P(0<= x <=17) = binomcdf(180,1/7,17) = 0.0349 ============================================= You may also find this probability using a cumulative binomial table, EXCEL, or some on-line binomial probability site. Try searching with Google for "binomial probability". ============================================= Cheers, Stan H.