SOLUTION: In a random sample of 26 computers, the mean repair cost was $130 with a sample standard deviation of $36. Assume that the population is normally distributed.
a. Find the marg
Algebra.Com
Question 270107: In a random sample of 26 computers, the mean repair cost was $130 with a sample standard deviation of $36. Assume that the population is normally distributed.
a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest hundredths.
b. Find a 95% confidence interval for the population mean .
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a random sample of 26 computers, the mean repair cost was $130 with a sample standard deviation of $36. Assume that the population is normally distributed.
a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest hundredths.
E = 1.96 = 13.84
----------------------
b. Find a 95% confidence interval for the population mean
CI: 130-13.84 < u < 130+13.84
CI: 116.16 < u < 143.84
==========================
Cheers,
Stan H.
RELATED QUESTIONS
In a random sample of 60 computers, the mean repair cost was $150 with a standard... (answered by merlin694)
You are given the sample mean and the sample standard deviation Assume the population is... (answered by CPhill)
An automotive repair shop has determined that the average service time on an automobile... (answered by stanbon)
In a random sample of 60 refrigerators, the mean repair cost was $150.00 and the... (answered by VFBundy)
10. In a random sample of five microwave ovens, the mean repair cost was $70.00 and the... (answered by ewatrrr)
in a random sample of four microwave ovens, the mean repair cost was $60.00 and the... (answered by ewatrrr)
A microwave oven repairer says that the mean repair cost of damaged microwave ovens is... (answered by stanbon)
In a random sample of six mobile devices, the mean repair cost was $60.00 and the... (answered by Boreal)
A random sample of 50 four-year-old’s attending day care centers provided a yearly... (answered by ikleyn)