Of the 7 coins there are 6 non-quarters. If she doesn't get the quarter, then the only way she could fail to get less than 25 cents would be to get 2 dimes and 1 nickel. Since there are only 2 dimes, to fail she must get them both, and since there are 3 nickels she can get 2 dimes and 1 nickel exactly 3 ways. So the number of successful ways to get less than 25 cents is the number of ways to get any 3 of the the 6 non-quarters minus the 3 ways to get 2 dimes and a nickel. That is, (6C3 - 3) ways The number of ways of getting any 3 of the coins is 7C3. So the desired probability isThe correct choice is (A) Edwin