SOLUTION: if P(A)= 7/36, P(B)= 1/6, and P(A and B)= 0, what can you say about P(A or B)?

Question 263049: if P(A)= 7/36, P(B)= 1/6, and P(A and B)= 0, what can you say about P(A or B)?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
if P(A)= 7/36, P(B)= 1/6, and P(A and B)= 0, what can you say about P(A or B)?
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P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = (7/36) + (1/6) - 0
P(A or B) = 7/36 + 6/36 = 13/36
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Note: Since P(A and B) = 0, A and B are disjoint.
and P(A or B) is simply P(A) + P(B)
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Cheers,
Stan H.
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