# SOLUTION: Suppose that 10 numbers are select at random from the interval [0, 1]. Find the probability that the first 5 are less than 1/4 and at least one of the numbers is less than 1/10. s

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Suppose that 10 numbers are select at random from the interval [0, 1]. Find the probability that the first 5 are less than 1/4 and at least one of the numbers is less than 1/10. s      Log On

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 Click here to see ALL problems on Probability-and-statistics Question 258726: Suppose that 10 numbers are select at random from the interval [0, 1]. Find the probability that the first 5 are less than 1/4 and at least one of the numbers is less than 1/10. solve thisFound 2 solutions by Fombitz, Edwin McCravy:Answer by Fombitz(13828)   (Show Source): You can put this solution on YOUR website!The assumptions is that all numbers are equally likely. Choosing each number is an independent event. Answer by Edwin McCravy(8924)   (Show Source): You can put this solution on YOUR website!It hasn't occurred to the other tutor that although any one number is just as likely to be chosen as any other, it is not as likely that one will be chosen between two numbers close together as it is that one will be chosen between two numbers far apart. ---------------------------------------------------------------------- Suppose that 10 numbers are select at random from the interval [0, 1]. Find the probability that the first 5 are less than 1/4 and at least one of the numbers is less than 1/10. ``` Let's draw the interval [0, 1] and mark the point at A, the point at B, the point at C, and the point at D The probability of choosing a number between A and B is . The probability of choosing a number between A and C is . The probability of choosing a number between B and C is The probability of choosing a number between B and D is The desired probability = P(the first 5 are between A and C) MINUS P(the first 5 are between B and C AND the last 5 are between B and D) = = .0009317221656 Edwin```