SOLUTION: A bag conatains
5 green skittles
3 red skittles
2 orange skittles
6 yellow skittles
how many green skittles must be added to the bag so that the probability of radomly p
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Question 258078: A bag conatains
5 green skittles
3 red skittles
2 orange skittles
6 yellow skittles
how many green skittles must be added to the bag so that the probability of radomly picking a green skittle is 2/3? explain.
another question:
Twelve out of the 144 Shoe City Stores sell childrens clothing. You write the names of all the store locations on cards and select a card at random.
What is the probability of not picking a store location that sell children's clothing? JUSTIFY
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A bag conatains
5 green skittles
3 red skittles
2 orange skittles
6 yellow skittles
how many green skittles must be added to the bag so that the probability of radomly picking a green skittle is 2/3? explain.
Let the number to add be "x":
(5 + x)/(16 + x) = 2/3
Cross multiply to get:
15+3x = 32 + 2x
x = 17
=====================
another question:
Twelve out of the 144 Shoe City Stores sell children's clothing. You write the names of all the store locations on cards and select a card at random.
What is the probability of not picking a store location that sells children's clothing?
---
P(144-12)/144 = 11/12
=============================
Cheers,
Stan H.
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