SOLUTION: A bag contains 3 red marables and 5 purple marables. One marable is drawn at random and not replaced. Then a second marable is drawn at random. What is the probability that the fir
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Question 254694: A bag contains 3 red marables and 5 purple marables. One marable is drawn at random and not replaced. Then a second marable is drawn at random. What is the probability that the first marable is purple and the second one is red
Found 2 solutions by richwmiller, solver91311:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
marble not marable.
5/8 for a purple on first draw
3/7 for red on second draw because one marble is gone
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I have no idea what "marables" [sic] are, but I'll simply assume they are little round things sort of like marbles. There are 8 total in the bag and 5 of them are purple, so the probability that the first one is purple is 
. Once you have chosen the first marble, there are only 7 left in the bag since we are doing this without replacement, so the probability that the second marble is red, given that there are 3 red marbles remaining in the bag, is 
. So the total probability of these two independent events is:
\left(\frac{3}{7}\right)\ =\ \frac{15}{56}\ \approx 0.27)
John
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