SOLUTION: In how many ways can 8 instructors be assigned to six sections of a course in mathematics?
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Question 250675: In how many ways can 8 instructors be assigned to six sections of a course in mathematics?
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In how many ways can 8 instructors be assigned to six sections of a course in mathematics?
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Let the sections select the instructors:
8C6 = 8C2 = (8*7)/(1*2) = 28 ways
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Cheers,
Stan H.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
One presumes that each of the sections of the course is identical to the others, hence the order in which the instructors are assigned doesn't matter. The number of ways that 
things can be chosen from a collection of 
things where order doesn't matter is given by:
\ =\ \frac{n!}{k!(n\,-\,k)!})
Your problem asks the question how many ways are there to select 6 things from a collection of 8 things.
On the other hand, if my presumption about order is incorrect, you can use the same formula by simply removing the factor of 
from the denominator.
John
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