SOLUTION: a box contains 3 defective lights and 5 non-defective lights. The lights are tested one at a time without replacement. What is the probability that the 3 defective bulbs will be

Question 248281: a box contains 3 defective lights and 5 non-defective lights. The lights are tested one at a time without replacement. What is the probability that the 3 defective bulbs will be found in the first 3 tests?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a box contains 3 defective lights and 5 non-defective lights. The lights are tested one at a time without replacement. What is the probability that the 3 defective bulbs will be found in the first 3 tests?
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P(3 defective) = (3/5)(2/4)(1/3) = 2/20 = 1/10
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Cheers,
Stan H.
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