# SOLUTION: A random variable X can assume two values 1 and 3. If its mean is 8/3, compute: the probabilities for those two points and the variance of X

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 Click here to see ALL problems on Probability-and-statistics Question 248090: A random variable X can assume two values 1 and 3. If its mean is 8/3, compute: the probabilities for those two points and the variance of XAnswer by stanbon(57361)   (Show Source): You can put this solution on YOUR website!A random variable X can assume two values 1 and 3. If its mean is 8/3, compute: the probabilities for those two points ---------------- Let probability of "1" be x Then probability of "3" is 1-x ---------------------------------- Mean = 1*x + 3(1-x) = 8/3 x + 3 - 3x = 8/3 -2x = 8/3 - 9/3 -2x = -1/3 x = 1/6 (Probability of "1") 1-x = 5/6 (Probability of "3") ================================== I'll let you figure the variance. ================================== Cheers, Stan H.